The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringes from the centre is
Text Solution
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Two waves of a single source having an amplitude A interfere. The resulting amplitude
where A 1 = A 2 = A and δ δ = phase difference between the waves
⇒ ⇒ I r = I 1 + I 2 + 2 
When the maxima occurs at the center, δ δ = 0
⇒ ⇒ 
…(1)
Since the phase difference between two successive fringes is 2 π π , the phase difference between two points separated by a distance equal to one quarter of the distance between the two, successive fringes is equal to
δ δ = (2 π π ) 
radian
⇒ ⇒ 
…(2)
using (1) and (2), 
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